Answered

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I am trying to figure this question:

1 + tan^2A = Sec^2A

Sagot :

Answer:

see explanation

Step-by-step explanation:

Using the Pythagorean identity

cos²A + sin²A = 1 ( divide terms by cos²A )

[tex]\frac{cos^2A}{cos^2A}[/tex] + [tex]\frac{sin^2A}{cos^2A}[/tex] = [tex]\frac{1}{cos^2A}[/tex] , that is

1 + tan²A = sec²A ← as required

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