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26. Calculate the mass of hydrogen formed when 25 grams of aluminum reacts with excess hydrochloride acid. 2AI + 6HCl →l Al2Cl6 + 3H2
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Sagot :

Kykoyubi

Answer:

2.76 gram

Explanation:

2AI + 6HCl → 2AlCl3 + 3H2

  1. get the mol of aluminum => n = m / M = 25 / 27 = 0.925 (mol)
  2. get the ratio mol of Hydro => nH2 = 0.925 * 3 / 2 = 1.38 (mol)
  3. get weight of hydro mH2 = n x M = 1.38 x 2 = 2.76 (gram)

Answer

Al +2 HCl - AlCl2 + H2

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