sopniladangol2009
Answered

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Sagot :

Its a parallelogram

<C+<D=<A+<C

Also

AB||CD

[tex]\\ \rm\Rrightarrow <A+<B=180[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{1}{2}<A+\dfrac{1}{2}<B=\dfrac{1}{2}180[/tex]

[tex]\\ \rm\Rrightarrow <PAB+<ABP=90[/tex]

Using angle sum property

[tex]\\ \rm\Rrightarrow <APB=180-90=90[/tex]

Hence proved

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