Answered

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Experıment wıth systems of equatıons 2x+4y =8....(1)
2x+2y=2....(2) answer?

Sagot :

ghaithgh

Answer:

Solve by substitution;

2x +4y =8 ...(1)

[tex]2x + 4y = 8 \\ \\ 4y = 8 - 2x \\ \\ y = \frac{8 - 2x}{4} \\ \\ y = 2 - \frac{x}{2} [/tex]

We substitute y into the second equation.

2x + 2y=2 ... (2)

[tex]2x + 2y = 2 \\ \\ 2x + 2(2 - \frac{x}{2} ) = 2 \\ \\ 2x + 4 - x = 2 \\ \\ x + 4 = 2 \\ x = 2 - 4 \\ x = - 2[/tex]

And we substitute x into the equation y .

[tex]y = 2 - \frac{x}{2} \\ \\ y = 2 - \frac{( - 2)}{2} \\ \\ y = 2 + 1 \\ y = 3[/tex]

(x,y) —> (–2 , 3 )

I hope I helped you^_^

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