Considering that angles A and C are equal, and the sum of the internal angles of a triangle is 180º, we have that:
The measure of angle A is of: 48º.
The measure of angle B is of: 84º.
The measure of angle C is of: 48º.
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- Segments AC and CB have the same length, thus, angles A and C have the same measure, and then:
[tex]6(x - 3) = 4(x + 1)[/tex]
[tex]6x - 18 = 4x + 4[/tex]
[tex]2x = 22[/tex]
[tex]x = \frac{22}{2}[/tex]
[tex]x = 11[/tex]
[tex]6(11 - 3) = 6(8) = 48[/tex]
The measure of angle A is of: 48º.
The measure of angle C is of: 48º.
The sum of the internal angles of a triangle is of 180º, and this is used to find the measure of angle B.
[tex]mA + mB + mC = 180[/tex]
[tex]2(48) + mB = 180[/tex]
[tex]mB = 84[/tex]
The measure of angle B is of: 84º.
A similar problem is given at https://brainly.com/question/13216436