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Complete the equation of the line through (−10,3) and (-8,-8)

Sagot :

Answer:

[tex]\boxed{y = -5,5x - 52}[/tex]

Step-by-step explanation:

Equation of a straight line: y = kx + b

Points: (-10,3) and (-8,-8)

Сompose the system of equations:

[tex]\displaystyle \left \{ {{3=-10k + b} \atop {-8=-8k + b}} \right[/tex] [tex]\displaystyle \left \{ {{b= 3 + 10k} \atop {b=8k - 8}} \right \Longrightarrow 3 + 10k = 8k - 8[/tex]

[tex]3 + 10k = 8k - 8[/tex]

[tex]2k = -11|:2[/tex]

[tex]k = -5,5[/tex]

[tex]b = 3 + 10k = 3 + 10 \cdot ( -5,5) = 3 - 55 = -52[/tex]

[tex]y = -5,5x - 52[/tex]