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Sagot :
Hello there, this is how we will solve your problem.\
here is the equation you gave us.
[tex]{\huge{\boxed{\mathbb{EQUATION}}}[/tex]
[tex]\begin{bmatrix}-5x+y=-3\\ 3x-8y=24\end{bmatrix}[/tex]
we can isolate [tex]x[/tex] and say [tex]x=\frac{-3-y}{5}[/tex]
Now here is our equation, [tex]\begin{bmatrix}3\left(-\frac{-3-y}{5}\right)-8y=24\end{bmatrix}[/tex] After we simplify it we get [tex]\begin{bmatrix}\frac{9-37y}{5}=24\end{bmatrix}[/tex], solve this and we get that [tex]y=-3[/tex], Before we said [tex]x[/tex] equals [tex]-\frac{-3-y}{5}[/tex], So now we can plug in our value that [tex]y[/tex] equaled, and now we have [tex]\frac{-3-(-3)}{5}[/tex]. Two negatives equal a positive and we get that [tex]x=0[/tex].
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- [tex]y=-3[/tex]
- [tex]x=0[/tex]
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