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Evaluate.

16÷(2+1/2)2

(the 2 at the end is a 1 half to the 2 power)

Sagot :

PEMDAS, notice Parentheses is first, then Exponents 2nd

[tex]16\div\left(2 + \left( \frac{1}{2} \right)^2 \right)\implies 16\div\left(2 + \left( \frac{1^2}{2^2} \right) \right)\implies 16\div\left(2+\frac{1}{4} \right)[/tex]

now that the exponent got done, let's keep in the parentheses

[tex]16\div\left(\frac{2}{1}+\frac{1}{4} \right)\implies 16\div\left(\cfrac{8+1}{\underset{\textit{using this LCD}}{4}} \right)\implies 16\div \left( \cfrac{9}{4} \right)[/tex]

PEMDAS, after all that we'll do D, Division next

[tex]16\div \left( \cfrac{9}{4} \right)\implies \cfrac{16}{1}\div \cfrac{9}{4}\implies \cfrac{16}{1}\cdot \cfrac{4}{9}\implies \cfrac{64}{9}\implies 7\frac{1}{9}[/tex]

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this just some addition to your previous posting, since you kinda got spammed some

[tex]\stackrel{\stackrel{\textit{E first}}{\downarrow }}{2^3}+4\cdot 2-7\implies 8+4\cdot 2-7\implies 8+\stackrel{\stackrel{\textit{M second}}{\downarrow }}{8}-7\implies \stackrel{\textit{AS last from left to right}}{16-7\implies 9}[/tex]

notice, PEMDAS, P first and so on, AS are last, from left to right.