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What is the slope of the line that passes though the pair of points (7/2, -3) and (-1, 5/3)

Sagot :

Answer:

m=  [tex]\frac{-28}{27}[/tex]

Step-by-step explanation:

Step 1: Plug in given points into slope formula.

m= [tex]y^2-y1/x^2-x^1[/tex]

[tex](x^2, y^2)= (\frac{7}{2}, -3)[/tex]

[tex](x^1, y^1)=(-1 ,\frac{5}{3})[/tex]

m= [tex]\frac{5}{3} -(-3)/-1-\frac{2}{7}[/tex]

Step 2: Subtract.

m=[tex]\frac{14}{3} /\frac{-9}{2}[/tex]

Step 3: Simplify.

m=[tex]\frac{-28}{27}[/tex]

Explanation: Since we only need two points to find the slope of the line, the given points can be plugged into the slope formula. After that, simply subtract and simplify. If anything does not make sense or my work is wrong, please let me know. Thanks.

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