morganconn867
Answered

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Solve the quadratic equation numerically (using tables of x- and y- values). x squared + 2 x + 1 = 0
a. x = -1
c. x = -3
b. x = 1 or x = -3
d. x = 2 or x = -1

Sagot :

kpall

Answer:

a. x = -1

Step-by-step explanation:

For a quadratic equation like this it is usually more easier to use the factorisation method so I'm sorry but I can't do the tables of x and y method

[tex]ax^{2} +bx+c[/tex]

In factorisation, you find a number that multiplies to give c but also adds or subtracts to give b so in this example it would be:

[tex]x^{2} +2x+1=0[/tex]

1: 1 × 1 = 1

So 1 times 1 gives 1 but then 1+1 gives 2 which is the correct match for this quadratic

[tex](x+1)(x+1)=0[/tex]

Now to solve it you take one bracket and you solve it using the 0

[tex]x+1=0\\x= -1[/tex]

Because both the equations are the same the answer would be the same

:)

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