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What are the roots of 3x2 + 10 = 4x? A. B. C. D.

Sagot :

joshuacastillo13
4x=4x4
3x2+10=16
What are the numbers for A,b,c,d

Answer:

[tex]x=\frac{2}{3}\pm\frac{\sqrt{26}}{3}i[/tex]

Step-by-step explanation:

[tex]3x^2+10=4x\\\\3x^2-4x+10=0\\\\x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\ \\x=\frac{-(-4)\pm\sqrt{(-4)^2-4(3)(10)}}{2(3)}\\ \\x=\frac{4\pm\sqrt{16-120}}{6}\\ \\x=\frac{4\pm\sqrt{-104}}{6}\\ \\x=\frac{4\pm2\sqrt{26}i}{6}\\ \\x=\frac{4}{6}\pm\frac{2\sqrt{26}}{6}i\\\\x=\frac{2}{3}\pm\frac{\sqrt{26}}{3}i[/tex]

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