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Solve the following right triangles for the parts not
given:
a. A = 40°10'13", hypotenuse = 402.36 ft
b. A = 62°09'15", hypotenuse = 338.74 m
c. A = 36°22'10", adjacent side = 360.41 ft
d. Hypotenuse = 428.29 m, opposite side =
397.06 m
e. Hypotenuse = 409.31 ft, adjacent sider
274.82 ft
f. Opposite side = 375.82 m, adjacent side=
276.05 m

Sagot :

Right triangles are triangles that have the measure of one angle to be 90 degrees

How to calculate the missing parts

a. A = 40°10'13", hypotenuse = 402.36 ft

Convert the angle to degrees

[tex]A=40.17^o[/tex]

Start by calculating the opposite side using the following sine ratio

[tex]\sin(A) = \frac{Opposite}{Hypotenuse}[/tex]

So, we have:

[tex]\sin(40.17) = \frac{Opposite}{402.36}[/tex]

Cross multiply

[tex]Opposite = 402.36 * \sin(40.17)[/tex]

[tex]Opposite = 259.55[/tex]

The adjacent is then calculated using the following cosine ratio

[tex]\cos(A) = \frac{Adjacent}{Hypotenuse}[/tex]

So, we have:

[tex]\cos(40.17) = \frac{Adjacent}{402.36}[/tex]

Cross multiply

[tex]Adjacent = 402.36 * \cos(40.17)[/tex]

[tex]Adjacent = 307.46[/tex]

Hence, the missing parts are:

Adjacent = 307.46 and Opposite = 259.55

b. A = 62°09'15", hypotenuse = 338.74 m

Convert the angle to degrees

[tex]A=62.15^o[/tex]

Start by calculating the opposite side using the following sine ratio

[tex]\sin(A) = \frac{Opposite}{Hypotenuse}[/tex]

So, we have:

[tex]\sin(62.15) = \frac{Opposite}{338.74}[/tex]

Cross multiply

[tex]Opposite = \sin(62.15) *338.74[/tex]

[tex]Opposite = 299.50[/tex]

The adjacent is then calculated using the following cosine ratio

[tex]\cos(A) = \frac{Adjacent}{Hypotenuse}[/tex]

So, we have:

[tex]\cos(62.15) = \frac{Adjacent}{338.74}[/tex]

Cross multiply

[tex]Adjacent = \cos(62.15) * 338.74[/tex]

[tex]Adjacent = 158.25[/tex]

Hence, the missing parts are:

Adjacent = 158.25 and Opposite = 299.50

c. A = 36°22'10", adjacent side = 360.41 ft

Convert the angle to degrees

[tex]A=36.37^o[/tex]

Start by calculating the hypotenuse using the following cosine ratio

[tex]\cos(A) = \frac{Adjacent}{Hypotenuse}[/tex]

So, we have:

[tex]\cos(36.37) = \frac{360.41}{Hypotenuse}[/tex]

Make Hypotenuse the subject

[tex]Hypotenuse = \frac{360.41}{\cos(36.37)}[/tex]

[tex]Hypotenuse = 447.60[/tex]

The opposite side is then calculated using the following cosine ratio

[tex]\sin(A) = \frac{Opposite}{Hypotenuse}[/tex]

So, we have:

[tex]\sin(36.37) = \frac{Opposite}{447.60}[/tex]

Cross multiply

[tex]Opposite = 447.60 * \sin(36.37)[/tex]

[tex]Opposite = 265.43[/tex]

Hence, the missing parts are:

Hypotenuse = 447.60 and Opposite = 265.43

d. Hypotenuse = 428.29 m, opposite side =397.06 m

The adjacent is calculated as:

[tex]Adjacent = \sqrt{Hypotenuse^2 - Opposite^2[/tex]

So, we have:

[tex]Adjacent = \sqrt{428.29^2 - 397.06^2[/tex]

[tex]Adjacent = 160.55[/tex]

Hence, the missing part is:

Adjacent = 160.55

e. Hypotenuse = 409.31 ft, adjacent side = 274.82 ft

The opposite is calculated as:

[tex]Opposite= \sqrt{Hypotenuse^2 - Adjacent ^2[/tex]

So, we have:

[tex]Opposite= \sqrt{409.31^2 - 274.82^2[/tex]

[tex]Opposite= 303.33[/tex]

Hence, the missing part is:

Opposite= 303.33

f. Opposite side = 375.82 m, adjacent side= 276.05 m

The hypotenuse is calculated as:

[tex]Hypotenuse= \sqrt{Opposite^2 + Adjacent ^2[/tex]

So, we have:

[tex]Hypotenuse= \sqrt{375.82^2 + 276.05^2[/tex]

[tex]Hypotenuse= 466.31[/tex]

Hence, the missing part is:

Hypotenuse= 466.31

Read more about right triangles at:

https://brainly.com/question/2437195