maya9390
Answered

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how many grams Kl are needed to prepare 100.mL of 0.55M solution?​

Sagot :

Answer:

Explanation:

100mL = 0.1L

0.55 M = mol/0.1 L

mol = 0.055 mol

molar mass of KI = 165.998 g

0.055 * 165.998 = 9.13 g of KI

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