Answered

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Mark invests $9600 in two different accounts. The first account paid 14 %, the second account paid 6 % in interest. At
the end of the first year he had earned $1056 in interest. How much was in each accounts?

Sagot :

Answer:

3600 and 9600

Step-by-step explanation:

let both accounts be rep by and A and B. We then add the two accounts

a + b = 9600 .......... eqn 1

payment on he first account = 14%  14/100 =  0.14

payment on the second account = 6% , 6/100 = 0.06

0.14a + 0.06b = 1056 ...... eqn 2

from equation 1  a+ b = 9600

a = 9600 - b ( we then put that into eqn 2

0.14(9600 - b) + 0.06b = 1056

1344 - 0.14b + 0.06b = 1056

-0.08b = -288    ( divide both sides by 0.08b

b = 3600

since a =  9600 -b  

a = 9600 - 3600

a = 6000

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