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Sagot :
Answer:
[tex]\displaystyle \int\limits^4_3 {2x + 3} \, dx = 10[/tex]
General Formulas and Concepts:
Calculus
Integration
- Integrals
Integration Rule [Reverse Power Rule]: [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]
Integration Rule [Fundamental Theorem of Calculus 1]: [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]
Integration Property [Multiplied Constant]: [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]
Integration Property [Addition/Subtraction]: [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]
Area of a Region Formula: [tex]\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx[/tex]
Step-by-step explanation:
Step 1: Define
Identify.
y = 2x + 3
x-interval [3, 4]
x-axis
See attachment for graph.
Step 2: Find Area
- Substitute in variables [Area of a Region Formula]: [tex]\displaystyle A = \int\limits^4_3 {2x + 3} \, dx[/tex]
- [Integral] Rewrite [Integration Property - Addition/Subtraction]: [tex]\displaystyle A = \int\limits^4_3 {2x} \, dx + \int\limits^4_3 {3} \, dx[/tex]
- [Integrals] Rewrite [Integration Property - Multiplied Constant]: [tex]\displaystyle A = 2 \int\limits^4_3 {x} \, dx + 3 \int\limits^4_3 {} \, dx[/tex]
- [Integrals] Integrate [Integration Rule - Reverse Power Rule]: [tex]\displaystyle A = 2 \bigg( \frac{x^2}{2} \bigg) \bigg| \limits^4_3 + 3(x) \bigg| \limits^4_3[/tex]
- [Integrals] Integrate [Integration Rule - FTC 1]: [tex]\displaystyle A = 2 \bigg( \frac{7}{2} \bigg) + 3(1)[/tex]
- Simplify: [tex]\displaystyle A = 10[/tex]
∴ the area bounded by the region y = 2x + 3, x-axis, and the coordinates x = 3 and x = 4 is equal to 10.
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Learn more about integration: https://brainly.com/question/26401241
Learn more about calculus: https://brainly.com/question/20197752
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Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Integration
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