genzmintz
Answered

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Trigonometric Equations

Solve the equation over the interval [0°, 360°)

2sin^2theta-5sintheta+3=0

Sagot :

agravanteandrei

Step-by-step explanation:

The solutions are

S

=

{

30

º

,

150

º

,

270

º

}

Explanation:

The equation is

2

sin

2

θ

+

sin

θ

−

1

=

0

We can factorise the LHS

(

2

sin

θ

−

1

)

(

sin

θ

+

1

)

=

0

Therefore,

sin

θ

=

−

1

,

⇒

,

θ

=

270

º

sin

θ

=

1

2

,

⇒

,

θ

=

30

º

,

150

º

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