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A 1.2-kg hot iron sphere with heat capacity
576 J °C-1 is cooled by immersing it in a tank of
water (Fig g). (See the photo that I uploaded)The mass of the water is 3 kg and
its initial temperature is 12 °C. After 5 minutes,
both the iron sphere and the water reach a final
temperature of 15 °C.

(a) Find the energy gained by the water.
(b) Find the average rate of energy transfer from
the iron sphere to the water.
(c) What is the initial temperature of the iron
sphere?

A 12kg Hot Iron Sphere With Heat Capacity 576 J C1 Is Cooled By Immersing It In A Tank Of Water Fig G See The Photo That I UploadedThe Mass Of The Water Is 3 Kg class=

Sagot :

Eduard22sly

Given the data from the question, the heat gained by the water, the rate of energy transfer and the initial temperature of the iron are:

A. The energy gained by the water is 37656 J

B. The average rate of energy transfer from

the iron sphere to the water is 125.52 J/s (Watts)

C. The initial temperature of the iron

sphere is 65.4° C

A. How to determine the heat gained

  • Mass of water (M) = 3 Kg = 3 × 1000 = 3000 g
  • Initial temperature (T₁) = 12 °C
  • Final temperature (T₂) = 15 °
  • Change in temperature (ΔT) = 15 – 12 = 3 °C
  • Specific heat capacity (C) = 4.184 J/gºC
  • Heat (Q) =?

Q = MCΔT

Q = 3000 × 4.184 × 3

Q = 37656 J

B. How to determine the rate of energy transfer

  • Heat (Q) = 37656 J
  • Time (t) = 5 min = 5 × 60 = 300 s
  • Power (P) =?

Power = energy / time

Power = 37656 / 300

Power = 125.52 J/s (Watts)

C. How to determine the initial temperature of the iron

  • Mass of iron (M) = 1.2 Kg = 1.2 × 1000 = 1200 g
  • Heat capacity (C) = 576 J/ºC
  • Heat (Q) = 37656 J
  • Temperature (T) =?

Q = CT

37656 = 576 × T

Divide both side by 576

T = 37656 / 576

T = 65.4° C

Learn more about heat transfer:

https://brainly.com/question/10286596

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