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Sagot :
Answer:
She is incorrect
Step-by-step explanation:
[tex]\begin{aligned}\dfrac{1}{3}(9x+48)-12x & =\dfrac{9}{3}x+\dfrac{48}{3}-12x\\ & = 3x+16-12x\\& = 16-9x\end{aligned}[/tex]
[tex]\begin{aligned}-4(2x+4) & =(-4)2x+(-4)4\\& = -8x-16\end{aligned}[/tex]
As [tex]16-9x\neq -8x-16[/tex] then she is incorrect.
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