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A dolphin accelerates at -1.77m/s^2 for 3.33s and ends with a velocity of -8.77m/s. What is the displacement of the dolphin in that time

Sagot :

vf=vi+at

8.77=vi+1.77 x 3.33

8.77 = vi+5.8941

vi=2.8759

vf²=vi²+2ad

8.77²=2.8759²+2x 1.77 x d

76.9129=8.27 + 3.54d

d=19.39 m

Answer:

-19.39

Explanation: