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solve for x -
[tex]\bold{x {}^{2} + 5x + 6 = 0}[/tex]

ty! ~​

Sagot :

[tex] {x}^{2} + 5x + 6 = 0 \\ \\ {x}^{2} + 2x + 3x + 6 = 0 \\ \\ x(x + 2) + 3(x + 2) = 0 \\ \\ (x + 2)(x + 3) = 0 \\ \\ x + 2 = 0 \\ \\ x = - 2 \\ \\ x + 3 = 0 \\ \\ x = - 3.[/tex]

The value of x = -2 and -3 .

Answer:

hope it helps...

it has both co ordinate and factorization

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