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Sagot :
The Capacitive reactance of the capacitor is 3.22kΩ.
To find the answer, we have to study about the Capacitive reactance.
How to find the Capacitive reactance?
- It is given that,
[tex]C=9*10^{-8}F\\f=550Hz\\[/tex]
- Thus, the expression for capacitive reactance will be,
[tex]X_c=\frac{1}{2\pi fC}[/tex]
- By substituting values, we get,
[tex]X_c=\frac{1}{2\pi *550*9*10^{-8}} \\\\X_c=3.22*10^3Ohm.[/tex]
Thus, we can conclude that, the Capacitive reactance of the capacitor is 3.22kΩ.
Learn more about the Capacitive reactance here:
https://brainly.com/question/27853857
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