Answered

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consider the line y=9x-8 find the equation that is perpendicular to this line and passes through the point -8,3

Sagot :

The equation of line is y=-9x-69.

To solve this problem we need to know the concept of slope of line and equation of straight line.

Writing the standard form of line is in the form of y= mx+ c where m is the slope of line.

And we also know that the product of slope of a line perpendicular to the line is equal to -1.

Let us assume that the slope of required line is m'

So, m' × 9 = -1

  ⇒ m'= -9

Now, the equation of line will be;

   [tex](y-3)=-9(x+8)[/tex]

⇒ y-3=-9x-72

⇒ y=-9x-69    is the standard equation of line perpendicular to the given line y=9x-8.

To learn more about the equation of line visit the link:

https://brainly.com/question/2564656

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