Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
Answer:
2,849,370
Explanation:
1. We'll use the law: [(Molar×Volume)÷ number of moles] of the base, and [(Molar×Volume)÷number of moles] of acids.
2. The answer should be a "mass" (how many grams) of the base, so we'll use for the base this law: (mass÷molar mass×number of moles).
3. The molecular mass (or molar) of Ca(OH)
2 =1(Atomic mass of Ca)+2(Atomic mass of O) +2(Atomic mass of H)
=40+2(16)+2(1)
=40+32+2
=74
4. No. of moles would be 1 in the acid and base due to: 1 Ca(oH)² + 1 H²SO⁴ --> 1 CaSO⁴ +2H²O.
5. Volume should be used in Leter so: 45.3×10³.
6. Put all the given in the question and solve: (mass (x) unknown) ÷ (74×1) = (0.850×45.3×10³) ÷ (1)
7. Then: (x)÷74 = 38,505 --> 2,849,370.
Answer:
2.85 g
Explanation:
To solve this problem, we need to first write out a balanced equation for the reaction:
[tex]\boxed{\mathrm{Ca(OH)_2 + H_2SO_4 \rightarrow CaSO_4 + 2H_2O}}[/tex]
Next, we have to calculate the number of moles of [tex]\mathrm{H_2SO_4}[/tex] that will be neutralized:
no. of moles of [tex]\mathrm{H_2SO_4}[/tex] = concentration × volume/1000
= 0.850 × [tex]\frac{45.3}{1000}[/tex]
= 0.0385 mol
As we can see from the balanced equation above, the molar ratio of [tex]\mathrm{Ca(OH)_2}[/tex] and [tex]\mathrm{H_2SO_4}[/tex] are equal; therefore their mole numbers are also equal.
This means that 0.0385 moles of [tex]\mathrm{Ca(OH)_2}[/tex] will be required to neutralize the [tex]\mathrm{H_2SO_4}[/tex].
Now we can calculate the mass of [tex]\mathrm{Ca(OH)_2}[/tex] required:
mass = no. of moles × molar mass
= 0.0385 × [40 + 2×(16+1)]
= 0.0385 × 74
= 2.85 g (3 s.f.)
Therefore, 2.85 g of [tex]\mathrm{Ca(OH)_2}[/tex] will be needed.
We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.