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A fire truck is responding to an emergency. It accelerates from 0 to 66km/hr in 11 seconds. What is its rate of acceleration?13

Sagot :

We have the following:

In order to calculate it, it is essential that you know the acceleration formula

[tex]a=\frac{v_f-v_i}{t_f-t_i}[/tex]

vi, is 0 km/h or km/s

vf, is 66 km/h or 66 km/h * 1 h/ 3600 s = 0.018 km/s

replacing:

[tex]a=\frac{0.018-0}{11-0}=\frac{0.018}{11}=0.0031[/tex]

The rate of acceleration 0.0031 km/s^2 or 39600 km/h^2 (0.0031 km/s^2 * 3600^2 s^2/ 1 h^2)