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the graph represents Billy's speed on a recent trip . for which time. Is his rate of change negative? A. between 0 and 5 minutes B. between 5 and 10 minutes C. between 10 and 20 minutes D. between 20 and 25 minutes

The Graph Represents Billys Speed On A Recent Trip For Which Time Is His Rate Of Change Negative A Between 0 And 5 Minutes B Between 5 And 10 Minutes C Between class=

Sagot :

D.between 20 and 25 minutes ​

Explanation

Step 1

when you have 2 points of a lines, you can find the rate of change, using:

[tex]\begin{gathered} \text{rate of change= slope=}\frac{y_2-y_1}{x_2-x_1} \\ \text{where } \\ P1(x_1,y_1) \\ P2(x_2,y_2) \end{gathered}[/tex]

then

a) between 0 and 5 minutes

Let

P1(0,0)

P2(5,40)

apply the formula

[tex]rate_1=\frac{y_2-y_1}{x_2-x_1}=\frac{40-0}{5-0}=\frac{40}{5}=8[/tex]

b)between 5 and 10 minutes

Let

P1(5,40)

P2(10,50)

apply

[tex]rate_{2_{}}=\frac{y_2-y_1}{x_2-x_1}=\frac{50-40}{10-5}=\frac{10}{5}=2\text{ }[/tex]

c)between 10 and 20 minutes

Let

P1(10,50)

P2(20,50)

apply

[tex]\begin{gathered} rate_{3_{}}=\frac{50-50}{20-10}=\frac{0}{10}=0 \\ \end{gathered}[/tex]

d)between 20 and 25 minutes ​

Let

P1(20,50)

P2(25,40)

apply

[tex]\begin{gathered} rate_{4_{}}=\frac{y_2-y_1}{x_2-x_1}=\frac{40-50}{25-20}=\frac{-10}{5}=-2\Rightarrow negative \\ \end{gathered}[/tex]

so, the answer is D.between 20 and 25 minutes ​