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how do you solve quadratic using square roots?ex: 3/4(x+1)²=10

Sagot :

Answer:

Explanation:

First, we multiply both sides by 4/3 to get

[tex]\frac{4}{3}\cdot\frac{3}{4}(x+1)^2=10\cdot\frac{4}{3}[/tex][tex](x+1)^2=\frac{40}{3}[/tex]

Taking the square root of both sides gives

[tex]\sqrt[]{(x+1)^2}=\sqrt[]{\frac{40}{3}}[/tex][tex]x+1=\sqrt[]{\frac{40}{3}}[/tex]

Finally, subtracting 1 from both sides gives

[tex]\boxed{x=\sqrt[]{\frac{40}{3}}-1}[/tex]

which is our answer!