Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Can you help me it’s. 2 part question I can only add one picture at a time

Can You Help Me Its 2 Part Question I Can Only Add One Picture At A Time class=

Sagot :

Recall the definition of the composition between two functions:

[tex](f\circ g)(x)=f(g(x))[/tex]

Similarly, but not always the same:

[tex](g\circ f)(x)=g(f(x))[/tex]

Use the rules of correspondence of the functions f and g to find the compositions:

[tex]\begin{gathered} f(x)=6x-10 \\ g(x)=8-4x \end{gathered}[/tex]

Then:

[tex]\begin{gathered} (f\circ g)(x)=f(g(x)) \\ =6\cdot g(x)-10 \\ =6(8-4x)-10 \\ =6\cdot8-6\cdot4x-10 \\ =48-24x-10 \\ =-24x+38 \\ \\ \therefore(f\circ g)(x)=-24x+38 \end{gathered}[/tex]

On the other hand:

[tex]\begin{gathered} (g\circ f)(x)=g(f(x)) \\ =8-4\cdot f(x) \\ =8-4(6x-10) \\ =8-4\cdot6x-4\cdot-10 \\ =8-24x+40 \\ =-24x+48 \\ \\ \therefore(g\circ f)(x)=-24x+48 \end{gathered}[/tex]

Therefore, the answers are:

[tex]\begin{gathered} (f\circ g)(x)=-24x+38 \\ (g\circ f)(x)=-24x+48 \end{gathered}[/tex]