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If the center of a circle is at (5,-7)and its radius is 6, complete itsequation:(x- [ ? ]2 + (y -[])2 = []Enter

If The Center Of A Circle Is At 57and Its Radius Is 6 Complete Itsequationx 2 Y 2 Enter class=

Sagot :

The equation of a circle is :

[tex](x-h)^2+(y-k)^2=r^2[/tex]

where (h, k) is the center and r is the radius.

From the problem, the center is at (5, -7) and the radius is 6

So the equation will be :

[tex](x-5)^2+\lbrack y-(-7)\rbrack^2=36[/tex]

The answers from left to right is 5, -7 and 36