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Sagot :
T solve the question, we will make a system of equations
Let there are x children and y adults in that day
Since there are 303 people on that day, then
Add x and y, then equate the sum by 303
[tex]x+y=303\rightarrow(1)[/tex]Since the admission fee for children is $1.75
Since the admission fee for adults is $6.20
Since the park collected $1220 from admissions, then
Multiply x by 1.75 and y by 6.20, then add the products and equate the sum by 1220
[tex]1.75x+6.20y=1220\rightarrow(2)[/tex]Now, we have a system of equations to solve it
Multiply equation (1) by -6.20 to make the coefficients of y equal in values and different in signs
[tex]\begin{gathered} (-6.20)(x)+(-6.20)(y)=(-6.20)(303) \\ -6.20x-6.20y=-1878.60\rightarrow(3) \end{gathered}[/tex]Add equations (2) and (3) to eliminate y
[tex]\begin{gathered} (1.75x-6.20x)+(6.20y-6.20y)=(1220-1878.60) \\ -4.45x=-658.6 \end{gathered}[/tex]Divide both sides by -4.45
[tex]\begin{gathered} \frac{-4.45x}{-4.45}=\frac{-658.6}{-4.45} \\ x=148 \end{gathered}[/tex]Substitute x in equation (1) by 148 to find y
[tex]148+y=303[/tex]Subtract 148 from both sides
[tex]\begin{gathered} 148-148+y=303-148 \\ y=155 \end{gathered}[/tex]There were 148 children and 155 adults
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