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Find the equation of the line passing through the point (18, -5) and slope -8.y + 8x = 139y - 8x = 49y + 2x = -132y + 12x = 24

Sagot :

Given: The point and the slope below

[tex]\begin{gathered} Point:(18,-5) \\ slope=-8 \end{gathered}[/tex]

To Determine: The equation o fthe line passing through the given point and slope

Solution

The formula for finding the equation of a line passing through a point and slope is

[tex]\begin{gathered} Point:(x_1,y_1) \\ Slope=m \\ \frac{y-y_1}{x-x_1}=m \end{gathered}[/tex]

Substitute the given into the formula

[tex]\begin{gathered} \frac{y--5}{x-18}=-8 \\ \frac{y+5}{x-18}=-8 \end{gathered}[/tex][tex]\begin{gathered} y+5=-8(x-18) \\ y+5=-8x+144 \\ y+8x=144-5 \\ y+8x=139 \end{gathered}[/tex]

Hence, the equation of the line passing through the given point and slope is

y + 8x = 139