To find the area that is not shaded in the circle, find the shaded region of the triangle using the formula
[tex]\begin{gathered} A_{triangle}=\frac{b\cdot h}{2} \\ \end{gathered}[/tex]
replace the data
[tex]\begin{gathered} A_{triangle}=6\cdot\frac{3}{2} \\ A_{triangle}=\frac{18}{2} \\ A_{triangle}=9 \end{gathered}[/tex]
continue by finding the area of the circle using the formula
[tex]A_{circle}=\pi\cdot r^2[/tex]
replace data
[tex]\begin{gathered} A_{circle}=\pi\cdot(3)^2 \\ A_{circle}=9\pi \end{gathered}[/tex]
the next step is to substract the area of the triangle from the area of the circle
[tex]A_{total}=9\pi-9[/tex]
the final step is to simplify the answer
[tex]A_{total}=9(\pi-1)[/tex]