Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
First, we are going to calculate the area of the semicircle.
The area of a circle is given by the following expression:
[tex]\begin{gathered} A=\frac{\pi}{4}\text{ }\times D^2 \\ D=\text{ diameter} \\ A=\frac{\pi}{4}\text{ }\times(8)^2 \\ A=50.26 \end{gathered}[/tex]As in the figure we have a semicircle, we have to divide the value of the Area by 2,
[tex]\begin{gathered} \text{Area of the Semicircle= }\frac{50.26}{2} \\ \text{Area of the Semicircle= }25.13m^2 \end{gathered}[/tex]Now we have to calculate the area of the trapezoid,
[tex]\begin{gathered} A=\frac{a+b}{2}\times h \\ a=\text{ minor base} \\ b=\text{ major base} \\ h=\text{ height} \end{gathered}[/tex][tex]\begin{gathered} A=\frac{8+12}{2}\times4 \\ A=40m^2 \end{gathered}[/tex]Now we add both values, area of the semicircle and area of the trapezoid,
[tex]\begin{gathered} \text{Area semicircle + Area trapezoid = 25.13+40 } \\ \text{Area semicircle + Area trapezoid = 65.13} \end{gathered}[/tex]Answer= 65.13 square meters
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.