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Sagot :
1) First, let's rewrite the equation:
3 H2 + N2 ---> 2 NH3
If you need to make 467 L ammonia gas (NH3), let's find out how many moles of it do we need.
For this, we use the molar volume of gases: 22.4L/mol
So:
467 L ------ x mol
22.4 L ----- 1 mol
22.4x = 467
x = 20.8 mol of NH3
2) Now we use the proportion of the chemical equation to find out the quantity in moles of N2 (nitrogen gas):
1 mol of N2 ---- 2 mol of NH3
x mol of N2 ----- 20.8 mol of NH3
2x = 20.8
x = 10.4 mol of N2
3) Now we use the molar mass of N2 to find the quantity in grams that we need to start with:
molar mass N2 = 2x14 = 28 g/mol
Now we use the following equation:
mass = mole × molar mass
mass = 10.4 × 28 = 291.2 grams of Nitrogen Gas
Answer: 291.2 grams of Nitrogen Gas
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