Given:
The points on the line are,
[tex](\frac{3}{8},-\frac{1}{4})\text{ and (-}\frac{5}{16},\frac{1}{6})[/tex]
The slope of the line is calculated as,
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ (x_1,y_1)=(\frac{3}{8},-\frac{1}{4}) \\ (x_2,y_2)=\text{(-}\frac{5}{16},\frac{1}{6}) \\ m=\frac{\frac{1}{6}-(-\frac{1}{4})}{-\frac{5}{16}-\frac{3}{8}} \\ m=\frac{\frac{2}{6\times2}+\frac{3}{4\times3}}{-\frac{5}{16}-\frac{3\times2}{8\times2}} \\ m=\frac{\frac{2+3}{12}}{\frac{-5-6}{16}} \\ m=\frac{5}{12}\times\frac{16}{-11} \\ m=-\frac{20}{33} \end{gathered}[/tex]
Answer: slope is -20/33
