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Sagot :
[tex]0.6107[/tex]
1) The first thing we need to do in this question, is to find the sample space, i.e. the total number of outcomes, in this case, fishes.
[tex]262+382+181+336+190=1351[/tex]2) Since no one could pick simultaneously two types of fish, then we can tell that these events are mutually exclusive. So, we can write the following:
[tex]\begin{gathered} P(flounder)=\frac{262}{1351} \\ \\ P(black\:drum)=\frac{181}{1351} \\ \\ P(red\:drum)=\frac{382}{1351} \\ \\ P(drum\:or\:flounder)=\frac{262}{1351}+\frac{181}{1351}+\frac{382}{1351}=\frac{825}{1351}\approx0.6107 \end{gathered}[/tex]Note that by "drum" we are including black and red drum.
That is the answer.
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