Answered

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s Southern New Ham... t: This question is similar to Example 4 in "1-3 Reading and Participation Ac blications" in Module One. You can check your answers to part c and d to make right track. rectangle has perimeter 86 cm and its length is 1 cm more than twice its width. 1 the dimensions of a rectangle given that its perimeter is 86 cm and its leng e its width. ip your solution using the variables L for the length. W for the width, and P for the perimeter

Sagot :

You have that a rectangle has a perimeter of 86cm and its length is 1cm more than twice its width.

If W is the width and L is the length you can write the previous situation as follow:

part a:

2W + 2L = 86 perimeter of the rectangle

part b:

L = 2W + 1

replace the expression for y into the equation 2x + 2y = 86, just as follow:

2W + 2(2W + 1) = 86 expand the parenthesis

2W + 4W + 2 = 86 subtract 2 both sides and simplify like terms

6W = 86 - 2

6W = 84

W = 84/6

W = 14

L = 2W + 1 = 2(14) + 1 = 28 + 1 = 29

part c:

The length is 29 cm

part d:

The width is 14 cm

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