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Sagot :

We can use trigonometric functions to determine how far it is across the lake.

Here, use tangent of angle A:

[tex]\begin{gathered} \tan 40^o=\frac{a}{630} \\ 0.839=\frac{a}{630} \\ 0.839\times630=a \\ 528.632=a \end{gathered}[/tex]

Thus, the lake is 529 yards across.

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