Answered

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A wheel of radius 30.0 cm is rotating at a rate of 2.20 revolutions every 0.0910 s. What is the linear speed of a point on the wheels rim?

Sagot :

Explanation:

First, we need to calculate the frequency of the wheel, so if it is rotating at a rate of 2.20 revolutions every 0.0910 seconds, the frequency is:

[tex]f=\frac{2.20\text{ revolutions}}{0.0910\text{ seconds}}=24.16\text{ Hz}[/tex]

Then, the magnitude of the angular velocity is equal to:

[tex]w=2\pi f=2(3.14)(24.16)=151.9\text{ rad/s}[/tex]

Finally, we can calculate the linear speed as the angular velocity times the radius, so:

[tex]v=w\cdot r=(151.9\text{ rad/s)(30 cm) = 4557.04 m/s}[/tex]

Therefore, the linear speed is 45.47 m/s

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