Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
Solid A has five(5) rectangular blocks that are co-joined. The dimension of each, is 45miles by 90miles.
Thus,
[tex]\begin{gathered} Total\text{ surface area=5}\times Area\text{ of one rectangular block} \\ \text{Total Surface Area=5}\times(45\times90) \\ T\mathrm{}S\mathrm{}A=5\times4050 \\ T\mathrm{}S\mathrm{}A=20250mi^2 \end{gathered}[/tex]Solid B has five(5) rectangular blocks that are co-joined. The dimension of each, is 30mi by 60mi.
Thus,
[tex]\begin{gathered} \text{Total Surface Area= 5}\times Area\text{ of one rectangular block} \\ T\mathrm{}S\mathrm{}A=5\times(30\times60) \\ T\mathrm{}S\mathrm{}A=5\times1800 \\ T\mathrm{}S\mathrm{}A=9000mi^2 \end{gathered}[/tex]The ratio of the T.S.A of the similar solids is given below:
[tex]\begin{gathered} T\mathrm{}S\mathrm{}A_{solid\text{ A}}\colon T.S.A_{solid\text{ B}} \\ 20250\colon9000 \\ \text{Divide both by 2250, we have:} \\ 9\colon4 \end{gathered}[/tex]Hence, the correct option is Option A
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.
