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given that triangle DEF is a right triangle with acute angles D and F and right angle E, which trigonometric function would be equal to Sin(F).

Given That Triangle DEF Is A Right Triangle With Acute Angles D And F And Right Angle E Which Trigonometric Function Would Be Equal To SinF class=

Sagot :

EXPLANATION

We can represent this situation as shown as follows:

The expression of Sin(F) is equal to Sin F = Opposite/Hypotenuse = DE/DF

[tex]\sin F=\frac{Opposite}{\text{Hypotenuse}}=\frac{DE}{DF}[/tex]

The equivalent expression would be:

[tex]Cos\text{ D=}\frac{Adjacent}{\text{Hypotenuse}}=\frac{DE}{DF}[/tex]

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