Given:
The mass of the cup, m=0.40 kg
The pressure applied by the cup, P=1000 N/m²= 1000 Pa
To find:
The radius of the ring imprinted on the table.
Explanation:
The pressure is defined as the force per unit area.
Thus the pressure applied by the cup is given by,
[tex]\begin{gathered} P=\frac{F}{A} \\ =\frac{mg}{\pi r^2} \end{gathered}[/tex]
Where A is the area of the ring, g is the acceleration due to gravity, and r is the radius of the ring.
On rearranging the above equation,
[tex]r=\sqrt{\frac{mg}{P\pi}}[/tex]
On substituting the known values,
[tex]\begin{gathered} r=\sqrt{\frac{0.40\times10}{1000\pi}} \\ =0.036\text{ m} \\ =3.6\text{ cm} \end{gathered}[/tex]
Final answer:
Thus the radius of the ring imprinted on the table is 3.6 cm
Therefore the correct answer is option 3.
