Answered

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A line passes through the point (-1,-13) and has a slope of 6. An equation of the line is

A Line Passes Through The Point 113 And Has A Slope Of 6 An Equation Of The Line Is class=

Sagot :

Recall that the slope-intercept form of the equation of a line is:

[tex]y=mx+b,[/tex]

where m is the slope of the line and b is the y-intercept.

To take the given equation to its slope-intercept form, first, we multiply it by x+1 and get:

[tex]\begin{gathered} y+13=6(x+1), \\ y+13=6x+6. \end{gathered}[/tex]

Subtracting 13, we get:

[tex]\begin{gathered} y=6x+6-13, \\ y=6x-7. \end{gathered}[/tex]

Answer:

[tex]y=6x-7.[/tex]

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