Answered

Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Unit 5 Project 1. A projectile is fired upward from the ground with an initial velocity of 300 feet per second. Neglecting air resistance, the height of the projectile at any time I can be described by the polynomial function P(t) = -16ť + 3000 a. Find the height of the projectile when t = 1 second. b. Find the height of the projectile when t = 5 seconds. c. How long will it be until the object hits the ground? 2. A board has length (3x + 6x - 18) meters and width of 2x + 1 meters. The board is cut into three pieces of the same length a. Find the length of each piece. b. Find the area of each piece. c. Find the area of the board before it is cut. d. How is the area of each piece of the board related to the area of the board before it is cut? 3. A cubic equation has zeros at -2, 1, and 3. a. Write an equation for a polynomial function that meets the given conditions. b. Draw the graph of a polynomial function that meets the given conditions. 4. Alice was having a conversation with her friend Trina, who had a discovery to share: 10

Unit 5 Project 1 A Projectile Is Fired Upward From The Ground With An Initial Velocity Of 300 Feet Per Second Neglecting Air Resistance The Height Of The Projec class=

Sagot :

1)

The polynomial modelling this scenario is expressed as

P(t) = - 16t^2 + 300t

where

P(t) represents the height at time t

a) To find the height of the projectile when t = 1 second, we would substitute

t = 1 into the equation. Thus,

P(1) = - 16(1)^2 + 300(1)

P(1) = - 16 + 300 = 284

Height of projectile when t = 1 second is 284 feet

b) To find the height of the projectile when t = 5 second, we would substitute

t = 5 into the equation. Thus,

P(1) = - 16(5)^2 + 300(5)

P(1) = - 400 + 1500

Height of projectile when t = 5 second is 1100 feet

c) At the time when the object hits the ground, the height would be zero. This means that p(t) = 0

Thus, the equation would be

0 = - 16t^2 + 300t

Factoring out 4t from the right, we have

0 = - 4t(4t - 75)

- 4t = 0 or 4t - 75 = 0

t = 0/-4 or 4t = 75

t = 0 or t = 75/4

t = 0 or t = 18.75

It will take 18.75 seconds until the object hits the ground

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.