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Sagot :
We have two numbers x and y such that their difference is 12:
[tex]\begin{gathered} x-y=12 \\ \Rightarrow x=12+y \end{gathered}[/tex]Now, we take the product of them:
[tex]x\cdot y=(12+y)\cdot y=y^2+12y[/tex]The smallest result we can get is 0 (ignoring the negative numbers, because the meaning of "small" implies an absolute value). Looking at the expression above, it is 0 for y = 0. If y = 0 then x = 12, and the difference is:
[tex]x-y=12-0=12[/tex]And their product is:
[tex]x\cdot y=12\cdot0=0[/tex]
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