Answered

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An arithmetic sequence has a 10th term of 15 and 14th term of 35. show that the equation (y=mx+b) of this graph equals an =-30+(n-1)5.

Sagot :

The arithmetic sequence follows

[tex]a_n=-30+(n-1)5[/tex]

Lets see if the 10th term is 15 by replacing the n for 10

n=10

[tex]a_{10}=-30+(10-1)5[/tex][tex]a_{10}=-30+(9)5=-30+45=15[/tex]

Now, Lets see if the 14th term is 35 by replacing the n for 14

n=14

[tex]a_{14}=-30+(14-1)5[/tex][tex]a_{14}=-30+(13)5=-30+65=35[/tex]Then so, the sequence follows the equation an =-30+(n-1)5.
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