Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
[tex]\begin{gathered} \text{For Jessica} \\ m=\text{ 40.0 }kg \\ r=8.0\text{ m} \\ v_{Jessica}=1.3\text{ m/s} \\ F_{Jessica}=\frac{mv^2_{Jessica}}{r}=\frac{(\text{ 40.0 }kg)(1.3\text{ m/s})^2}{8.0\text{ m}} \\ F_{Jessica}=8.45N \\ \\ \text{For Julie} \\ m=\text{ 40.0 }kg \\ r=6.0\text{ m} \\ v_{Julie}=0.95\text{ m/s} \\ F_{Julie}=\frac{mv^2_{\text{Julie}}}{r}=\frac{(\text{ 40.0 }kg)(0.95\text{ m/s})^2}{6.0\text{ m}} \\ F_{Julie}=6.01\text{ N} \\ \\ \text{Jessica is experiencing the greatest force of }8.45N \end{gathered}[/tex]
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.
