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When 7 times a number is decreased by 1, the result is 9 more than 5 times the number?So I got this below: 7x-1 = 9+5yHow do I find the number?

Sagot :

5

1) Translating that into a mathematical expression, we can write out the following. Let's call this number by "n":

[tex]\begin{gathered} I)7n-1 \\ II)9+5n \\ 7n-1=9+5n \\ 7n-5n=9+1 \\ 2n=10 \\ \frac{2n}{2}=\frac{10}{2} \\ n=5 \end{gathered}[/tex]

Just one mistake: when we refer to the same number we use the same variable.