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A line passes through the point (4,7) and has slope of 5/4. Write an equation in slope intercept form for this line.

Sagot :

Given the point (4,7) and the slope 5/4, we can use the line equation in the form slope-point to get the following:

[tex]\begin{gathered} (x_0,y_0)=(4,7) \\ m=\frac{5}{4} \\ y-y_0=m(x-x_0) \\ \Rightarrow y-7=\frac{5}{4}(x-4)=\frac{5}{4}x-\frac{5\cdot4}{4}=\frac{5}{4}x-5 \\ \Rightarrow y=\frac{5}{4}x-5+7=\frac{5}{4}x+2 \\ y=\frac{5}{4}x+2 \end{gathered}[/tex]

therefore, the equation in slope intercept form is y = 5/4x + 2