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Sagot :
Mutually exclusive events:
Two events are mutually exclusive if they cannot occur at the same time.
There are 52 cards in a deck of cards.
n(s)=52.
Let A be event of getting jack.
n(A)=4.
So, Probability of getting jack is,
Let B be event of getting 4
n(B)=4.
So, Probability of getting 4 is,
[tex]\begin{gathered} P(B)=\frac{n(B)}{n(s)} \\ =\frac{4}{52} \end{gathered}[/tex]These two events do not occur at same time.
Therefore the events are mutually exclusive.
[tex]P(A\cap B)=0[/tex]To find the probability of getting jack or 4
[tex]P(\text{A }\cup\text{B)}=P(A)+P(B)-P(A\cap B)[/tex]hence,
[tex]\begin{gathered} P(\text{A }\cup\text{B)}=\frac{4}{52}+\frac{4}{52}-0 \\ =\frac{8}{52} \\ =\frac{2}{13} \end{gathered}[/tex]The probability of getting jack or 4 is,
[tex]\frac{2}{13}[/tex]
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