Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
Recall that the cosine ratio is determined by adjacent side, divided by the hypotenuse of a right triangle.
Given that cosine is 4/5, the opposite side is
[tex]\begin{gathered} a^2+b^2=c^2 \\ a^2+(4)^2=(5)^2 \\ a^2+16=25 \\ a^2=25-16 \\ a^2=9 \\ \sqrt{a^2}=\sqrt{9} \\ a=3 \end{gathered}[/tex]Now that we have solved for the opposite side, recall that cosecant is determined by the equation
[tex]\csc\theta=\frac{\text{hypotenuse}}{\text{opposite}}[/tex]Substitute
hypotenuse = 5
opposite = 3
and we get
[tex]\csc\theta=\frac{5}{3}\text{ \lparen final answer\rparen}[/tex]
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.
